2x^2-21x-725=0

Solution for 2x^2-21x-725=0 equation:

2x^2-21x-725=0

a = 2; b = -21; c = -725;
Δ = b2-4ac
Δ = -212-4·2·(-725)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-79}{2*2}=\frac{-58}{4}
=-14+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+79}{2*2}=\frac{100}{4}
=25
$